-4.9x^2+850=0

Solution for -4.9x^2+850=0 equation:

-4.9x^2+850=0

a = -4.9; b = 0; c = +850;
Δ = b2-4ac
Δ = 02-4·(-4.9)·850
Δ = 16660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16660}=\sqrt{196*85}=\sqrt{196}*\sqrt{85}=14\sqrt{85}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{85}}{2*-4.9}=\frac{0-14\sqrt{85}}{-9.8}
=-\frac{14\sqrt{85}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{85}}{2*-4.9}=\frac{0+14\sqrt{85}}{-9.8}
=\frac{14\sqrt{85}}{-9.8}
$